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=2Y^2-64
We move all terms to the left:
-(2Y^2-64)=0
We get rid of parentheses
-2Y^2+64=0
a = -2; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-2)·64
Δ = 512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{512}=\sqrt{256*2}=\sqrt{256}*\sqrt{2}=16\sqrt{2}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{2}}{2*-2}=\frac{0-16\sqrt{2}}{-4} =-\frac{16\sqrt{2}}{-4} =-\frac{4\sqrt{2}}{-1} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{2}}{2*-2}=\frac{0+16\sqrt{2}}{-4} =\frac{16\sqrt{2}}{-4} =\frac{4\sqrt{2}}{-1} $
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